Kev-wilson
Tele-Meister
I feel like I either misunderstood the course title or misread the classroom numberI feel like the guy at the back of the class who's hoping the professor doesn't call on to answer questions.![]()


I feel like I either misunderstood the course title or misread the classroom numberI feel like the guy at the back of the class who's hoping the professor doesn't call on to answer questions.![]()
@andrewRneumann correct, but frequency times capacitance times resistance is not really a ratio.
@andrewRneumann I see what you're getting at now. Since resistance and current are inversely proportional, and Merlin gives the following formula for finding capacitance (C) from peak to peak (Vpp) ripple voltage, given a DC load current (I) and mains voltage frequency (f):
C = I / (2 f Vpp)
Yes, exactly. I = Vdc/Rl. Substitute that in for I and you will get 2 x f x C x Rl equalling the ratio of Vdc : Vpp (ripple). f in this case is mains frequency, so the factor "2" is in there for full-wave rectification. My above example forgot to take into account the 2, so it is off by a factor of 2. I will fix it... again... *hangs head*.