Cjteleforum
Tele-Meister
The AC voltage on the filaments of the 6V6 in my Champ is reading 7.2 V. Please let me know if this the proper way to lower it to 6.3 V.:
7.2V - 6.3V is .9V. 9V/.45 Amps(the current draw of a 6V6)=2 ohm resistor. The wattage is the voltage drop, .9V * .45 amps=.4 watts * 5=2 watts.
So I need to wire two 2 ohm 2 watt resistors from the filament wires to the heater pins, 2 and 7, of the 6V6?
Is that right?
Also, is is safe for the PT? All the other voltages in the amp are reading right.
Any advice much appreciated.
7.2V - 6.3V is .9V. 9V/.45 Amps(the current draw of a 6V6)=2 ohm resistor. The wattage is the voltage drop, .9V * .45 amps=.4 watts * 5=2 watts.
So I need to wire two 2 ohm 2 watt resistors from the filament wires to the heater pins, 2 and 7, of the 6V6?
Is that right?
Also, is is safe for the PT? All the other voltages in the amp are reading right.
Any advice much appreciated.