I'm working on a Revibe build. I was looking at the schematic, and it seems that bypassing the harmonic tremolo (either by foot switch or by intensity rolled to 0) doesn't really "bypass" the harmonic tremolo section, it just turns off the oscillator:
So there's is never really a fully "dry" bypassed signal, there's just a signal that has the effect rolled down to 0. This can be okay, if the frequency response of the system is flat when in bypass (for a reasonable guitar sonic-range, like 100hz to 8000ish hz). I guess I could test this out with my oscilloscope once the build is done, but I was wondering if anyone has a more theoretical explanation. I don't fully understand exactly what is happening when this is in bypass, I only really know that generally when it's on, the circuit has a low pass and a high pass filter modulated at 180 degrees out of phase from each other.
Can anyone explain how the circuit works when it's in bypass, and whether we can tell from looking at the schematic whether the frequency response should be flat?

So there's is never really a fully "dry" bypassed signal, there's just a signal that has the effect rolled down to 0. This can be okay, if the frequency response of the system is flat when in bypass (for a reasonable guitar sonic-range, like 100hz to 8000ish hz). I guess I could test this out with my oscilloscope once the build is done, but I was wondering if anyone has a more theoretical explanation. I don't fully understand exactly what is happening when this is in bypass, I only really know that generally when it's on, the circuit has a low pass and a high pass filter modulated at 180 degrees out of phase from each other.
Can anyone explain how the circuit works when it's in bypass, and whether we can tell from looking at the schematic whether the frequency response should be flat?
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