# Ex 11.2, 6 - Chapter 11 Class 7 Perimeter and Area

Last updated at Dec. 12, 2018 by Teachoo

Last updated at Dec. 12, 2018 by Teachoo

Transcript

Ex 11.2, 6 DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (Fig 11.24). If the area of the parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL. Here, We can find area of parallelogram using: AB as base & DL as height Or AD as base & BM as height Given, Area = 1470 cm2 Base = AB = 35 cm Height = DL = ? Area of parallelogram = Base × Height 1470 = AB × DL 1470 = 35 × DL 1470/35 = DL 210/5 = DL 42 = DL DL = 42 cm 1470/35 = DL 210/5 = DL 42 = DL DL = 42 cm Given, Area = 1470 cm2 Base = AB = 35 cm Height = DL = ? Area of parallelogram = Base × Height 1470 = AB × DL 1470 = 35 × DL Using AD & BM Given, Area = 1470 cm2 Base = AD = 35 cm Height = BM = ? Area of parallelogram = Base × Height 1470 = AD × BM 1470 = 49 × BM 1470/35 = DL 210/5 = DL 42 = DL DL = 42 cm 1470/49 = BM 210/7 = BM 30 = BM BM = 30 cm ∴ Length of DL is 42 cm and Length of BM is 30 cm

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.