Check out our newest website for Fender lovers -- TalkFender.com

Olav · February 2nd, 2012, 01:38 PM

Peeps, I'm redoing the wiring in my Hagström Select Ultra Swede. It has 1 Volume and 1 Tone pot. Also featured are coilsplitting and the obvious pup selector for bridge and neck. What I'd like is the switching flexibilty an LP has but on two knobs (this making sense?).I'm planning on replacing the V and T pots with concentric pots to give me that. Being a lefty I'd highly prefer reverse tapered pots. Anybody know where to get those? Thanks.

jkingma · February 2nd, 2012, 01:54 PM

If you were 25 years older you would have been forced to be right handed as a kid and you wouldn't have these problems.

Olav · February 2nd, 2012, 02:01 PM

I'd probably not be playing the guitar if I were forced to be a 'right'y. That's a discussion I'm not willing to enter anymore though. I know it's a long shot, but I thought if I were to ask anywhere... here would be a good place to do it.

jkingma · February 2nd, 2012, 02:10 PM

Danelectro made a lot of lefty guitars and most of theirs had concentric pots... but knowing Dano, they probably used righty pots.

If I find any source, I'll let you know.

crazydave911 · February 2nd, 2012, 02:24 PM

Ok, I'll bite finally. I've just took apart three pots out of my junkbox (three different brands too). I don't see one blessed thing that makes them "righty" or "lefty". Shouldn't wiring a pot opposite of standard convention, by default make them a "lefty"? Help me understand this

mlp-mx6 · February 2nd, 2012, 02:56 PM

The taper of an audio pot would determine righty-ness or lefty-ness. Reverse audio would be what a lefty wants. For linear pots (not generally used on guitars) it would be a non-issue.

Olav · February 2nd, 2012, 04:03 PM

John, thanks, if you do find anything please do let me know.
Dave, I blow at explaining this but you can trust me on this. Reverse soldering a regular pot isn't gonna do the trick. 100% volume for 75% (or more with some) of the way and a sudden steep drop for the last 25%.
MLP; All concentric knobs I found are audios though (which isn't a surprise of course), so that's what makes this hard.
Thanks fellas.

jefrs · February 2nd, 2012, 04:43 PM

No problem with linear pots stacked or otherwise, ok for lefty or righty.

Reverse-log pots are log/audio pots that work backwards, would work for lefty as an audio-log pot (if wired backwards). I have never seen a stacked one.

You can convert a linear pot to pseudo-log by fitting a fixed resistor of R=0.83Vr between wiper and ground (you have to double the value of the pot too - a 500k Vr + 420k R makes 220k) if you switch which end is ground you get a left-handed (reverse-log) one. This does work for potentiometers but I need to think about how to rig the rheostat variable resistor for the tone control ...
So "10" is full Vr resistance in series with the cap, ok. So if the hot connection is at the "0" end and the cap is on the wiper then the fixed goes between wiper and "10". I have not tested this one.

otterhound · February 2nd, 2012, 04:46 PM

I've never found any . Doesn't mean that they don't exist somewhere . Possibly could be sourced in Japan if they exist anywhere .

Olav · February 2nd, 2012, 05:10 PM

Quote:

Originally Posted by jefrs

No problem with linear pots stacked or otherwise, ok for lefty or righty.

Reverse-log pots are log/audio pots that work backwards, would work for lefty as an audio-log pot (if wired backwards). I have never seen a stacked one.

You can convert a linear pot to pseudo-log by fitting a fixed resistor of R=0.83Vr between wiper and ground (you have to double the value of the pot too - a 500k Vr + 420k R makes 220k) if you switch which end is ground you get a left-handed (reverse-log) one. This does work for potentiometers but I need to think about how to rig the rheostat variable resistor for the tone control ...
So "10" is full Vr resistance in series with the cap, ok. So if the hot connection is at the "0" end and the cap is on the wiper then the fixed goes between wiper and "10". I have not tested this one.

Let me get this straight. I'm planning on rewiring a humbucker guitar, I'll typically want 500k pots for that. So, I start out with 1Meg pots, than place a resistor between wiper and ground. What value resistor do I need for this? Can't wrap my tiny brain round the reverse logic... Now I know how Dave felt. Not saying you got as tiny a brain as mine Dave...

jkingma · February 2nd, 2012, 08:00 PM

Quote:

Originally Posted by Olav

...Not saying you got as tiny a brain as mine Dave...

Sounds like ya are...

crazydave911 · February 2nd, 2012, 08:22 PM

Quote:

Originally Posted by jkingma

Sounds like ya are...

Too danged funny

Olav · February 3rd, 2012, 03:25 AM

That Kingma feller is in a strange mood... Must be the sudden rush of wooddust.

I have a couple leads to read up on that tell how to trick out a linear pot to do what Jefrs suggested.

But today the snow came to my part of the world, so I'm working...

jkingma · February 3rd, 2012, 11:06 AM

Quote:

Originally Posted by Olav

That Kingma feller is in a strange mood... Must be the sudden rush of wooddust.

Ain't the wood dust... it's all the other $hi!t life keeps dumping on me...

jefrs · February 4th, 2012, 08:19 PM

Quote:

Originally Posted by Olav

Let me get this straight. I'm planning on rewiring a humbucker guitar, I'll typically want 500k pots for that. So, I start out with 1Meg pots, than place a resistor between wiper and ground. What value resistor do I need for this? Can't wrap my tiny brain round the reverse logic... Now I know how Dave felt. Not saying you got as tiny a brain as mine Dave...

Like what I said R = 0.83 x Vr

0.83 x 1Meg = 830k

Nearest preferred value R is 820k.

Put this across wiper to ground and you get 450k which will be near enough 500k
This will be a pseudo-logarithmic pot for most of its travel. Do note that audio pots consist of 3 or 4 linear tracks laid end to end, to describe their operation as logarithmic requires a poetic license.

However as you reduce the volume to zero, the load on the pickup will increase to 1Meg, which may make the output a little brighter.

I'm either-handed. I find it very confusing when confronted with pots wired backwards. I always expect clockwise to increase volume.

Me. I'd fit a linear vol pot anyway - 500k linear for a full humbucker.

jefrs · February 4th, 2012, 08:24 PM

Quote:

Originally Posted by otterhound

I've never found any . Doesn't mean that they don't exist somewhere . Possibly could be sourced in Japan if they exist anywhere .

You are not looking very hard
http://www.cricklewoodelectronics.co...me.php?cat=489

Also Farnell, RS etc etc

February 2nd, 2012, 01:38 PM	#1 (permalink)
Olav Tele-Holic Join Date: Apr 2010 Location: HLMRmeer Age: 44 Posts: 951	??Lefty Stacked Concentric Pots?? Peeps, I'm redoing the wiring in my Hagström Select Ultra Swede. It has 1 Volume and 1 Tone pot. Also featured are coilsplitting and the obvious pup selector for bridge and neck. What I'd like is the switching flexibilty an LP has but on two knobs (this making sense?).I'm planning on replacing the V and T pots with concentric pots to give me that. Being a lefty I'd highly prefer reverse tapered pots. Anybody know where to get those? Thanks. __________________ va' sa' du? va' hete' du? check my guitars@LGTf

February 2nd, 2012, 01:54 PM	#2 (permalink)
jkingma Poster Extraordinaire Join Date: Nov 2006 Location: N 44° 59.564 ~ W 079° 35.317 Posts: 8,679 18 Photos	If you were 25 years older you would have been forced to be right handed as a kid and you wouldn't have these problems. __________________ Creator of Fine Sawdust and Expensive Kindling.

February 2nd, 2012, 02:01 PM	#3 (permalink)
Olav Tele-Holic Join Date: Apr 2010 Location: HLMRmeer Age: 44 Posts: 951	I'd probably not be playing the guitar if I were forced to be a 'right'y. That's a discussion I'm not willing to enter anymore though. I know it's a long shot, but I thought if I were to ask anywhere... here would be a good place to do it. __________________ va' sa' du? va' hete' du? check my guitars@LGTf

February 2nd, 2012, 02:10 PM	#4 (permalink)
jkingma Poster Extraordinaire Join Date: Nov 2006 Location: N 44° 59.564 ~ W 079° 35.317 Posts: 8,679 18 Photos	Danelectro made a lot of lefty guitars and most of theirs had concentric pots... but knowing Dano, they probably used righty pots. If I find any source, I'll let you know. __________________ Creator of Fine Sawdust and Expensive Kindling.

February 2nd, 2012, 02:24 PM	#5 (permalink)
crazydave911 Friend of Leo's Join Date: Feb 2010 Location: East Tennessee Age: 52 Posts: 2,816 2 Photos	Ok, I'll bite finally. I've just took apart three pots out of my junkbox (three different brands too). I don't see one blessed thing that makes them "righty" or "lefty". Shouldn't wiring a pot opposite of standard convention, by default make them a "lefty"? Help me understand this __________________ "No trees were harmed in the creation of this message, however some electrons were temporarily inconvenienced." My Facebook

Sponsored Ads	#
Forum Sponsor Sponsored posting Join Date: March, 2003 Location: Forum HQ Age: Posts: N/A	Sponsored by...

February 2nd, 2012, 02:56 PM	#6 (permalink)
mlp-mx6 Tele-Meister Join Date: Jan 2008 Location: Atlanta Age: 49 Posts: 392	The taper of an audio pot would determine righty-ness or lefty-ness. Reverse audio would be what a lefty wants. For linear pots (not generally used on guitars) it would be a non-issue.

February 2nd, 2012, 04:03 PM	#7 (permalink)
Olav Tele-Holic Join Date: Apr 2010 Location: HLMRmeer Age: 44 Posts: 951	John, thanks, if you do find anything please do let me know. Dave, I blow at explaining this but you can trust me on this. Reverse soldering a regular pot isn't gonna do the trick. 100% volume for 75% (or more with some) of the way and a sudden steep drop for the last 25%. MLP; All concentric knobs I found are audios though (which isn't a surprise of course), so that's what makes this hard. Thanks fellas. __________________ va' sa' du? va' hete' du? check my guitars@LGTf

February 2nd, 2012, 04:43 PM	#8 (permalink)
jefrs Poster Extraordinaire Join Date: Nov 2007 Location: Newbury, England Age: 57 Posts: 8,370 4 Photos	No problem with linear pots stacked or otherwise, ok for lefty or righty. Reverse-log pots are log/audio pots that work backwards, would work for lefty as an audio-log pot (if wired backwards). I have never seen a stacked one. You can convert a linear pot to pseudo-log by fitting a fixed resistor of R=0.83Vr between wiper and ground (you have to double the value of the pot too - a 500k Vr + 420k R makes 220k) if you switch which end is ground you get a left-handed (reverse-log) one. This does work for potentiometers but I need to think about how to rig the rheostat variable resistor for the tone control ... So "10" is full Vr resistance in series with the cap, ok. So if the hot connection is at the "0" end and the cap is on the wiper then the fixed goes between wiper and "10". I have not tested this one. __________________ There's two kinds of people, those that hear the music and those that don't.

February 2nd, 2012, 04:46 PM	#9 (permalink)
otterhound Friend of Leo's Join Date: Dec 2008 Location: Manheim Pa. Posts: 3,474 12 Photos	I've never found any . Doesn't mean that they don't exist somewhere . Possibly could be sourced in Japan if they exist anywhere .

February 3rd, 2012, 03:25 AM	#13 (permalink)
Olav Tele-Holic Join Date: Apr 2010 Location: HLMRmeer Age: 44 Posts: 951	That Kingma feller is in a strange mood... Must be the sudden rush of wooddust. I have a couple leads to read up on that tell how to trick out a linear pot to do what Jefrs suggested. But today the snow came to my part of the world, so I'm working... __________________ va' sa' du? va' hete' du? check my guitars@LGTf

Check out our newest website for Fender lovers -- TalkFender.com

IMPORTANT:Treat everyone here with respect, no matter how difficult! No sex, drug, political, religion or hate discussion permitted here.