True bypass "pop"

Know I've seen this somewhere.. But how do you stop a switch from popping hen you switch it? I know it either a resistor or a capacitor but I can't remember which or what value?
Thanks,
Foster

Resistor from input to ground and another from output to ground with a value of 1 megohm.(you can increase the value but it isn´t necessary)I am talking about a pedal.If you have a switch that switches from A to B you can connect a 10 meg ohm resistor between A and B.

Resistor from input to ground and another from output to ground with a value of 1 megohm.(you can increase the value but it isn´t necessary)I am talking about a pedal.If you have a switch that switches from A to B you can connect a 10 meg ohm resistor between A and B.

What about a switch that switches between two resistor values? It's a DPDT with the resistors on each sides and in and out on the common lugs

I made a preamp for guitar in a stompbox where I switched between two different resistances which gave me two different amount of gain.! resistor gave me unity gain and the another was a variable resistor.(A pot where I used two lugs).The resistor was always in the circuit and the pot was normally shorted by the stomp switch for rhythm.For solos you stomped on the switch which removed the short for pot which was connected in series with the resistor.Now I got a gain which depended on the resisistor+ the resistance of the pot which I had preset.No clicks at all..Cant you modify the circuit so there is always one resistor in the circuit and when you switch you put another resistor in parallell with the first one which gives you the resistance you want?
Maybe I have misunderstood you.In that case come back with a circuit diagram or a more detailed explanation.

scroll down to offboard wiring number 5 for a diagram on how to wire your footswitch with grounded bypass. http://www.tonepad.com/getFile.asp?id=76 My experience is that if you do this you should have no pop. This requires no pulldown resistor, I have built several pedals wired this way and no pop on any of them. On the other hand, if you have a defective footswitch it may result in a pop no matter what you do.

I am talking about a pedal.If you have a switch that switches from A to B you can connect a 10 meg ohm resistor between A and B.

You mean like replacing the jumper from lug 7 to 9 on a 3PDT switch with a 10meg resistor?

1- 2- 3-

4- 5- 6-

7- 8- 9-

Google millennium bypass...

You mean like replacing the jumper from lug 7 to 9 on a 3PDT switch with a 10meg resistor?

1- 2- 3-

4- 5- 6-

7- 8- 9-

If 8 is the lug that in one position connects to 7 and in the other position is connected to 9,yes.Normally the pull down resistors (1 Meg from the input to ground and the other 1 Meg resistor from output to ground, will suffice.)
When I write 1 Meg from the input,I mean the effects input,not the input to the box where you plug in.Likewise for the output.The output from the circuit.If I am being unclear,please come back and ask what I meant.English isn´t my first language!

^ Sorry,really not positive about the mechanics of the 3pdt or which lug is actually connecting to which lug during switching.Heres how I wire my 3pdt's. So, instead of the jumper from 7-----9 , I can use a resistor?

Sorry,I must have explained badly.No,you don´t cut any jumpers.I think you should try pulldown resistors.If you go to www.muzique.com/news/pulldown-resistors/ you will find a very good explanation of why you need them and how you connect them.Even though your switch is different the schematic is valid.One pulldown-resistor from the effects input to ground and one from the effects output also to ground.The article explains in detail why the resistors shouldn´t be connected from the jacks to the ground, so read it,find the input and output and solder!