$vboptions[bbtitle]



Effects pedal pricing?

dhuber
January 4th, 2011, 01:03 PM
Effects pedal pricing is one thing that I don’t understand. For example I just bought two new Boss OD pedals today: OD-3 and SD-1. In my thinking we have a metal box a few capacitors, resistors, and transistors. Yet I paid $75 for the OD-3 and $40 for the SD-1. I don’t get it. Is it a marketing thing or priced by popularity? I can see paying more for a loop or delay if a pedal has to have huge amounts of memory in it. But when they just have basically the same components inside I don’t understand. I can also see paying more if the pedal is handmade or has point to point wiring.

vedt
January 4th, 2011, 01:13 PM
There are many things that could impact pricing. Sure, there's parts. But there's also labor. If it's easy for a guy on the manufacturing line to screw up a delay pedal, then more labor costs go into that pedal. Also, pricing is strategic, not just based on the exact input costs plus a mark-up. There's also marketing costs. If T-Rex needs to do a bunch of online marketing to get their name out, then their pedals will cost more, even if the parts costs the same amount as a Boss pedal. Also, the parts might be similar in a Boss SD-1 vs. a Fulltone OCD. But Boss might be trying to undercut the market and make up their low margin by selling a ton more pedals than Fulltone. Where as Mike Fuller may want his products to be known as being top-of-the-line. And any overdrive priced less than, say, $100 is perceived to be "non-boutique".

Again, there are many, many things that go into pricing. Material costs. Supply & demand. Pricing strategy considerations. Marketing costs.

11 Gauge
January 4th, 2011, 01:27 PM
Effects pedal pricing is one thing that I don’t understand. For example I just bought two new Boss OD pedals today: OD-3 and SD-1. In my thinking we have a metal box a few capacitors, resistors, and transistors. Yet I paid $75 for the OD-3 and $40 for the SD-1. I don’t get it. Is it a marketing thing or priced by popularity? I can see paying more for a loop or delay if a pedal has to have huge amounts of memory in it. But when they just have basically the same components inside I don’t understand. I can also see paying more if the pedal is handmade or has point to point wiring.

The SD-1 is old old old technology, and has long since "paid for itself," just for starters. It's a combination of the OD-1 and a TS (the OD-1 had no tone control). The OD-1 was released in '77, and the SD-1 was released in '81.

The OD-3 was designed and created by Boss in '97. Not only is it an original overdrive circuit, much of it uses "discrete" components instead of a singular dual op amp integrated circuit, like the SD-1. Discrete means individual transistors, which are trickier to set up to bias properly (when a zillion of these things are designated to be built). Not only that, but Roland/Boss doesn't "skimp" on the particular type of transistors used in the OD-3: they are nice Toshiba units.

...So the OD-3 has a bit of design costs that justify the higher price (relative to the SD-1), they obviously had to tool up to produce it, and there might be other cost-per-unit issues (it hasn't been as popular as the BD-2, for starters). All of that said, they did just drop the price a bit. I think that the more pedal savvy crowd who are familiar with the BD-2 are starting to experience the OD-3, and many prefer it.

Boss should have chosen a more appealing color for the OD-3, or just something different from yellow, since guitarists equate it with the SD-1 (it also has the same 3 knob format).

IMO, the OD-3 is the best Boss dirt box in the line, stock out of the box. Well worth 2X the cost of the SD-1.

jimmynumber9
January 4th, 2011, 01:31 PM
You also have to think of the amount of engineering that it took to make that pedal sound the way it does. If you could just throw some random electronics into an aluminum case and call it a phaser then I'm sure pedals would cost a lot less and they could all be home made. You pay for the specific sound you are getting out of that pedal as well.